A galvanic cell's voltage drops to zero at equilibrium because the electrical potential of the two half-cells becomes perfectly equal. The cell produces voltage by allowing a spontaneous redox reaction to occur. At equilibrium, the forward and reverse reactions proceed at the exact same rate, meaning no net work can be done and no electrons can flow through the external circuit. As the cell operates, products are formed and reactants are consumed, driving the reaction quotient Q toward the equilibrium constant K. At chemical equilibrium, Q = K.
Because there is no longer a driving force for the reaction, the Gibbs free energy change Delta G equals zero. Consequently, the cell potential Ecell drops to exactly '0'volts.
Mathematicaly we know that
Delta G = -nFEcell = -(nF)V = - (total charge transfered) x Voltage = work done by the cell = loss in its potential energy.
so Delta G = 0 is possible only when Ecell = 0
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